Sand Hill is a summit located in Central New York Region of New York located in the Town of Russia in Herkimer County, east-northeast of Poland.

Sand Hill
Sand Hill Location of Sand Hill within New York Show map of New York Sand Hill Sand Hill (the United States) Show map of the United States
Highest point
Elevation	1,542 feet (470 m)
Coordinates	43°15′31″N 75°00′53″W[1]
Geography
Location	ENE of Poland, New York, U.S.
Topo map	USGS Hinckley

References