Fleurus Island is an island lying 1 km (0.5 nmi) south of Delaite Island in Wilhelmina Bay, off the west coast of Graham Land, Antarctica. it was shown on an Argentine government chart of 1950, and was named by the UK Antarctic Place-Names Committee in 1956 after the British ship Fleurus, which visited the area in 1928.[1]

Fleurus Island

Fleurus Island Location in Antarctica Show map of Antarctica Fleurus Island Fleurus Island (Antarctic Peninsula) Show map of Antarctic Peninsula
Geography
Location	Antarctica
Coordinates	64°34′S 62°13′W
Administration
Administered under the Antarctic Treaty System
Demographics
Population	Uninhabited

See also

• List of Antarctic and sub-Antarctic islands

References

 This article incorporates public domain material from the United States Geological Survey document: "Fleurus Island". (content from the Geographic Names Information System)

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