Champoeg Creek is a tributary, roughly 6 miles (9.7 km) long, of the Willamette River in the U.S. state of Oregon. The creek is formed by the confluence of its two forks in the French Prairie region of the Willamette Valley and flows generally northeast to meet the Willamette 45 miles (72 km) from the river's confluence with the Columbia River. Its course lies entirely in Marion County.[3][4]

Champoeg Creek
The creek near Champoeg Road, looking north
Location of the mouth of Champoeg Creek in Oregon
Location
Country	United States
State	Oregon
County	Marion County
Physical characteristics
Source	French Prairie
• coordinates	45°11′02″N 122°55′49″W[1]
• elevation	121 ft (37 m)[2]
Mouth	Willamette River
• location	near Champoeg
• coordinates	45°15′14″N 122°52′56″W[1]
• elevation	62 ft (19 m)[1]
Length	6 mi (9.7 km)[3]

The name "Champoeg" comes from the Kalapuyan word [čʰámpuik], which might be an abbreviation of [čʰa-čʰíma-púičuk], referring to the edible root [púičuk], or yampa.[5]

Course

The creek begins at the confluence of East Fork Champoeg Creek and West Fork Champoeg Creek in French Prairie and flows generally northeast. The East Fork is about 5 miles (8.0 km) long, and the West Fork is about 6 miles (9.7 km) long. Not far from its source, Champoeg Creek enters McKay Reservoir then Spada Reservoir, where it passes under St. Paul Highway Northeast. Shortly thereafter, it receives Murphy Creek from the left. It passes under McKay Road Northeast and Champoeg Road Northeast before receiving Case Creek from the right and Mission Creek from the left in Champoeg State Heritage Area. Less than 1 mile (1.6 km) later, it enters the Willamette River 45 miles (72 km) from the larger stream's mouth on the Columbia River.[3][4]

See also

• List of rivers of Oregon

References