Stevenson Island is a small, uninhabited island in Yellowstone Lake, Teton County, Wyoming.[1] It was originally called Stevenson's Island[2] after Colonel James D. Stevenson,[3] and is now sometimes called Stevensons Island.[4]
![]() ![]() Stevenson Island (Wyoming) | |
Geography | |
---|---|
Location | Wyoming |
Coordinates | 44°30′50″N 110°23′02″W |
Total islands | 1 |
Highest elevation | 2,366 m (7762 ft) |
Administration | |
United States | |
Demographics | |
Population | 0 |
The island is long and narrow, lying in a generally north–south orientation. At the widest, it is about 250 metres (820 ft), and the length is about 1,800 metres (1.1 mi) long.[5] It is about 2.5 kilometres (1.6 mi) from the west shore of Yellowstone Lake, where Weasel Creek enters the lake.[6]
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