Leskov Island is an ice-covered island in the West Ice Shelf of Antarctica, rising to 185 metres (600 ft), 11 kilometres (6 nmi) northwest of Mikhaylov Island. It was discovered by the First Russian Antarctic Expedition of 1819–21, and named after Lieutenant Leskov, one of the members of that expedition.[1]

Leskov Island

Leskov Island Location in Antarctica
Geography
Location	Antarctica
Coordinates	66°36′S 85°10′E
Area	49.5 km2 (19.1 sq mi)
Length	9 km (5.6 mi)
Width	5.5 km (3.42 mi)
Highest elevation	185 m (607 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Population	Uninhabited

References

 This article incorporates public domain material from the United States Geological Survey document: "Leskov Island". (content from the Geographic Names Information System)

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